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Find x sothat 9, x, 4 are consecutive terms of a G.P. solve cheyyu |
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Answer» if the TERMS are in GP then they are in the FORM: a, a.r, a.r²,so on......here terms are 9,x,4Therefore,a=9; a.r=x; a.r²=4a.r²/a=4/9r²=4/9√r²=√2*2/3*3r=2/3a.r²/r=a.r4/(2/3)=X4*3/2=xx=2*3x=6 |
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