Find zero of p(x)=3x^2+5x+2

1.	Find zero of p(x)=3x^2+5x+2
Answer» ANSWER: $3 {x}^{2} + 5x + 2 = 0 \\ = 3 {x}^{2} + 3x + 2x + 2 = 0 \\ = 3x(x + 1) + 2(x + 1) = 0 \\ = (x + 1)(3x + 2) = 0 \\ x = - 1 \: \: and \: \: \frac{ - 2}{3}$ HEY! MATE Here is your SOLUTION. THANKS

Answer»

$3 {x}^{2} + 5x + 2 = 0 \\ = 3 {x}^{2} + 3x + 2x + 2 = 0 \\ = 3x(x + 1) + 2(x + 1) = 0 \\ = (x + 1)(3x + 2) = 0 \\ x = - 1 \: \: and \: \: \frac{ - 2}{3}$

HEY! MATE Here is your SOLUTION. THANKS

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Find zero of p(x)=3x^2+5x+2

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