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Findout the position of the image formed and draw the appropriate ray diagram. u = –30 cm R = + 10 cm |
Answer» Solution :`n_(2)/v-n_(1)/U=(n_(2)-n_(1))/R`  `RARR 1.5/v+1/30=0.5/10` `rArr 1.5/v=0.5/10-1/30` `rArr 1.5/v=0.5/30` `rArr v=+90` Mirror will from the image of `I_(1)` 30 cm behind it as shown in the figure. For the second REFRACTION : `u=-150` cm `R=-10` cm `n_(1)=1.5` `n_(2)=1` `1/v+1.5/150=(-0.5)/(-10)` `rArr 1/v=0.5/10-1/100` `rArr 1/v=4/100` `rArr v=25` cm (Real) |
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