1.

Finkelstein reaction for the preparation of alkyl iodide is based upon the fact that:

Answer»

Sodium iodide is soluble in METHANOL, while sodium chloride is insoluble in methanol.
Sodium iodide is solublc in methanol, while NaCl and NaBr are insoluble in mcthanol.
Sodium iodide is insolublc in methanol, while NaCl and NaBr are soluble.
The three halogens differ CONSIDERABLY in their electronegativity

Solution : `R-X+underset(("Solube" in CH_3OH,Me_2CO))NaIoverset("ACETONE")rarrR-I+underset(("Insolube" in CH_3OH,Me_2CO))NaXdarr`(where X = Cl or Br)


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