1.

Five capacitors each of capacitance C and breakdown voltage V are connected as shown in the figure. The capacitance and breakdown voltage of the combination (applid across AB) will be

Answer»

`(7C)/(6), V/2`
`(7C)/(6),V`
`(7C)/(60), (3V)/(2)`
`(6C)/(7), V/2`

Solution :USE voltage DIVIDER rule and concept of series and parallel combination of capacitor
`C_(AB) = (Cxx2C)/(C+2C) +(CxxC)/(C+C)`
`=(2C)/(3) +C/2 = (7C)/(6)`
Also , breakdown voltage of combination will be `(3V)/(2)`


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