Saved Bookmarks
| 1. |
Five charges,q each are placedof the corners of a regular pentagon of side 'a' Fig. (a) (i)What will be the electric field at 0, the centerof the pentagon ? (ii) What will be the electricfield at 0 if the charge from one of the corners (say A) is removed ? (iii) What will be the electric fieldat 0 if the charge q at A is replacedby-q ? (b) How would your answerto (a) be affectedif pentagon is replaced by n-sided regular polygon with chargeq at each q at each of its corners ? |
|
Answer» SOLUTION :(a) (i) In fig, the electric field at 0, the center of pentagon wouldbe zero. (ii) When charge q from corner A is REMOVED , electricfield at 0 WOULD be `E_(1) = (q xx 1)/(4pi in_(0) R^(2))` along OA. (III) If charge q at A is replacedby `-q`, it is equivanlent to addingcharge `-2q` at A. Therefore, electric field at 0 would be `E_(2) = (2q)/(4pi in_(0) r^(2))` along OA. (b) When pentagon is replacedby n sides regular polygon withcharge q at each of its corners, the electricfieldat 0 would continuebe to zero. |
|