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Five different games are to be distributed among 4 children randomly.The probability that each child get at least one game is`1//4`b. `15//64`c. `5//9`d. `7//12` |
Answer» Correct Answer - D Total ways of distribution = `n(S) = 4^(5)` Total ways of distribution so that each child get at least one game `n(E) = 4^(5) - .^(4)C_(1) 3^(5) + .^(4)C_(2) 2^(5) - .^(4)C_(3)` `=1024 - 4 xx 243 + 6 xx 32 - 4 = 240` Required probability `p = (n(E))/(n(S)) = (240)/(4^(5)) = (15)/(64)` |
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