Five identical capacitors, of capacitance 20muF each , are connected to a battery of 150V , in a combination as shown in the diagram . Whatis the total amount of charge stored ?

Five identical capacitors, of capacitance 20muF each , are connected t

1.	Five identical capacitors, of capacitance 20muF each , are connected to a battery of 150V , in a combination as shown in the diagram . Whatis the total amount of charge stored ?
Answer» `15xx10^(-3)C` `12xx10^(-3)C` `10xx10^(-3)C` `3xx10^(-3)C` Solution : Now at balance condition no current will PASS through BD CONSISTING of `20muF` capacitor. Therefore , EQUIVALENT CIRCUIT will be Equivalent capacitance of ABC path = Equivalent capacitance of ADC path `=(20xx20)/(20+20)=(400)/(40)=10MUF` So,equivalent capacitance of the circuit, `C_(eq)=10+10=20muF` `therefor` Total amountof charge stored `=C_(eq)xxV` `=(20xx10^(-6)xx150)=3000xx10^(-6)C=3xx10^(-3)C`

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Five identical capacitors, of capacitance 20muF each , are connected to a battery of 150V , in a combination as shown in the diagram . Whatis the total amount of charge stored ?

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