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Five point charges each of charges +q are placed of five vertices of a regular hexagon of side 'l'. Find the magnitude of the resultant force on a charge -q placed at the centre of the hexagon.(##U_LIK_SP_PHY_XII_C01_E09_018_Q01.png" width="80%"> |
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Answer» Solution :From the adjoining it is that force on -q charge placed at centre point Odue to A and B are respectively balanced by force due to D and E respectively. ` therefore ` MAGNITUDE of resultant force =Force due to charge C ` "" =F= (1)/(4 PI in _0) .((q)(q))/(l^(2)) ` `RARR "" F= (1)/(4pi in _0) .(q^(2))/(l^(2))` |
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