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Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages. |
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Answer» Let Five years AGO the age of SON be X years and age of father be 7X yearsPresent age of son =x+5Present age of father =7x+55 years LATER their age will (x+10) and (7x+10)∴7x+10=3(x+10)7x−3x=204x=20x=5So, the present age of son=x+5=5+5=10yearsand the present age of father=7x+5=35+5=40years |
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