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Five years ago a man was seven times as old as his son. Five years hence,the father will be three times as old as his son.Find their present ages? |
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Answer» 5Step-by-step explanation:Let FIVE YEARS ago the AGE of son be x years and age of FATHER be 7x years Present age of son =x+5 Present age of father =7x+5 5 years later their age will (x+10) and (7x+10) ∴7x+10=3(x+10) 7x−3x=20 4x=20 x=5 So, the present age of son=x+5=5+5=10years and the present age of father=7x+5=35+5=40yearsi hope it help u |
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