five years ago, father was seven times as old as his son. Five years hence, the father will be three times as Five old as his son. Find their present ages.

five years ago, father was seven times as old as his son. Five years h

1.	five years ago, father was seven times as old as his son. Five years hence, the father will be three times as Five old as his son. Find their present ages.
Answer» -step explanation:LET FIVE years ago the AGE of son be x years and age of father be 7X yearsPresent age of son =x+5Present age of father =7x+55 years later their age will (x+10) and (7x+10)∴7x+10=3(x+10)7x−3x=204x=20x=5So, the PRESENT age of son=x+5=5+5=10yearsand the present age of father=7x+5=35+5=40years

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five years ago, father was seven times as old as his son. Five years hence, the father will be three times as Five old as his son. Find their present ages.​

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five years ago, father was seven times as old as his son. Five years hence, the father will be three times as Five old as his son. Find their present ages.