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Fluorine is the most reactive of all four common halogens. |
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Answer» Solution :`F_(2)` is most reactive of all the FOUR common halogens (`F_(2), Cl_(2), Br_(2) and I_(2)`) because of the following reasons : (i) `F_(2)` has the LOWEST bond dissociation enthalpy. (ii) The bonds formed between F and most of the elements are much stronger than those formed by other halogens. (iii) `F_(2)` has the highest electrode potential (+ 2.8+N397 V) of the four halogens, therefore, `F_(2)` is the STRONGEST oxidising AGENT and hence can be reduced more readily as compared to `Cl_(2), Br_(2) and I_(2)`. |
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