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Focal length of a convex lense in air is `10cm`. Find its focal length in water. Given that `mu_g=3//2` and `mu_w=4//3`.A. 2.5 cmB. 5 cmC. 20 cmD. 40 cm |
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Answer» Correct Answer - D `(1)/(f_1)=(._amu_g-1)((1)/(R_1)-(1)/(R_2))` …(i) `(1)/(f_(omega))=(._(omega)mu_g-1)((1)/(R_1)-(1)/(R_2))` ….(ii) `f_(omega)/(f_(a))=((._amu_(g)-1))/((._omegamu_(g)-1))=((._amu_(g)-1))/(((._amu_(g))/(._amu_omega)-1))` `(f_(omega))/(10)=(((3)/(2)-1))/(((3//2)/(4//3)-1))=4impliesf_(omega)=40cm` |
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