1.

Following data is known about melting of a compound AB. DeltaH=9.2 kJ mol^(-1), DeltaS=0.008 kJ K^(-1) mol^(-1). Its melting point is

Answer»

736 K
1050 K
1150 K
`1150^(@)C`

Solution :`T_(m)=(DeltaH_("FUSION"))/(DeltaS_("fusion"))=(9.2)/(0.008)=1150 K`.


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