Following figure shows two process A and B for a gas. If `Delta Q_(A)` and `Delta Q_(B)` are the amount of heat absorbed by the system in two case, and `Delta U_(A)` and `Delta U_(B)` are changes in internal energies, respectively, then : A. (a) `DeltaQ_1=Delta_2, DeltaU_1=DeltaU_2`B. (b) `DeltaQ_1gtDeltaQ_2,DeltaU_1gtDeltaU_2`C. (c) `DeltaQ_1ltDeltaQ_2,DeltaU_1ltDeltaU_2`D. (d) `DeltaQ_1gtDeltaQ_2,DeltaU_1=DeltaU_2`

Following figure shows two process A and B for a gas. If `Delta Q_(A)`

1.	Following figure shows two process A and B for a gas. If `Delta Q_(A)` and `Delta Q_(B)` are the amount of heat absorbed by the system in two case, and `Delta U_(A)` and `Delta U_(B)` are changes in internal energies, respectively, then : A. (a) `DeltaQ_1=Delta_2, DeltaU_1=DeltaU_2`B. (b) `DeltaQ_1gtDeltaQ_2,DeltaU_1gtDeltaU_2`C. (c) `DeltaQ_1ltDeltaQ_2,DeltaU_1ltDeltaU_2`D. (d) `DeltaQ_1gtDeltaQ_2,DeltaU_1=DeltaU_2`
Answer» Correct Answer - D `W_1gtW_2` as area under graph-`alpha` is more. Hence, `DeltaQ_1gtDeltaQ_2`, as `DeltaQ=W+DeltaU` and `DeltaU_1=DetlaU_2`

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