1.

Following is the distribution of I.Q of 100 students. Find the median I.Q. I. Q: 55 - 64  65 - 74 75 - 84 85 - 84 95 - 104 105 - 114 115 - 124 125 - 134 135 - 144 No. of students: 1 2 9 22 33 22 8 2 1

Answer»
 Class interval (exclusive) Class interval (inclusive) Frequency Cumulative frequency
 55 - 64 54.5 - 64.511
 65 - 74 64.5 - 74.523
 75 - 84 74.5 - 84.5912
 85 - 94 84.5 - 94.52234 (F)
 95 - 104 94.5 - 104.533 (f)37
 105 - 114 104.5 - 114.52289
 115 - 124 114.5 - 114.5897
 125 - 134 114.5 - 124.5299
 135 - 144 134.5 - 144.51100
 N = 100

We have, 

N = 100

\(\frac{N}{2}=\frac{100}{2}=50\)

The cumulative frequency just greater than \(\frac{N}{2}\) s 67 then the median class 94.5-104.5 such that,

l = 94.5, f = 33, F = 34, h = 104.5 – 94.5 = 10

Median = I + \(\frac{\frac{N}{2}-F}{f}\times h\)

\(=94.5+\frac{50-34}{33}\times10\)

\(=94.5+\frac{16}{33}\times10\)

\(=94.5+4.85=99.35\)



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