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Following is the probability density function `f(x)=pxe^(-4x^2),0lexleoo` . Then the value of p isA. 8B. 5C. 7D. -1 |
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Answer» Correct Answer - A `oversetoounderset0intf(x)dx=1` `rArr" "oversetoounderset0intpxe^(-4x^2)dx=1rArrp[e^(-4x^2)/(-8)]_0^oo=1` `[{:(therefore"put"-4x^2=trArrxdx=(dt)/(-8)),(thereforeinte^t(dt)/(-8)=e^t/(-8)=e^(-4x^2)/(-8)):}]` `rArr" "(-p)/8[1/e^(4x^2)]_0^oo=1rArr(-p)/8[1/oo-1/1]=1` `rArr" "p/8=1rArrp=8` |
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