1.

Following solutions at the same temperature will be isotonic

Answer»

3.42 g of cane sugar in one litre water and 0.18 g of glucose in one litre water
3.42 g of cane sugar in one litre water and 0.18 g of glucose in 0.1 litre water
3.42 g of cane sugar in one litre water and 1.17 g of NaCl in one litre water
3.42 g of cane sugar in one litre water and 1.17 g of NACI in one litre water

Solution :For ISOTONIC solution, `pi_(1) = pi_(2)`
(andfor nonelectrolytes also `C_(1) = C_(2))`
`pi_(1) = W/(M xx V) xx RT = 3.42 /(342 xx 1)RT = 0.01 RT`
`pi_(2) = 0.18/(180 xx 0.1) RT = 0.01 RT`


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