1.

For 1 mole of an ideal gas, a graph of pressure vs volume is plotted as shown. Which of the following options is correct ?

Answer»

AB process is isothermal
Maximum temperature of the gas can be `10/0.0821 K`
Minimum temperature of the gas can be `11/(4xx0.0821) K`
NONE of these

Solution :`P-1=(10-1)/(1-10) (V=10)`
`P=-V+10`
`RT=-V^(2)+11V`
`(RDT)/(dV)=-2V+11=0`
`V=1/2`
`T_(max)=(-121/4+11xx11/2)/R=121/(4xx0.0821)K`


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