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For 10 minute each, at 27^(@)C, from two identical holes nitrogen and an unknown gas are leaked into a common vessel of 3 litre capacity. The resulting pressure is 4.18 bar and the mixture contains 0.4 mole of nitrogen. What is the molar mass of unknown gas ? |
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Answer» Solution :P=4.18 bar, V=3L, T=300 K `n_(T) =(PV)/(RT) =(4.18xx3)/(0.83xx300)=0.50` Total mole of gases diffused =0.50 Mole of UNKNOWN GAS `n_(g)` diffused `=n_(T)-n_(N_(2))` `=0.50 -0.40=0.10` `(n_(g)//t_(g))/(n_(g)//t_(n_(2)))=sqrt((M_(n_(2))/(M_((g))))` `rArr =(0.1)/(0.4) =sqrt((28)/(M_((g)))` `rArr Mg =448" gm mole "^(-1)` |
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