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For a 1^(st) order reaction (gaseous) (constant V, T) : aAto(b-1)B+1 C(with bgta) the pressure of the system rose by 50(b/a-1) %in a time of 10 min. The half life of the reaction is therefore.

Answer»

10 MIN
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Solution :`{:(AA,to,(B-a)B,+C),(t=0,P_0,0,0),(t=t,P_3x,((b-a)x)/a,x/a):}`
Total PRESSURE `P_0-x+b/ax=P_0+(b/a-1) 1/2 P_0`
`P_0+(b/a-1)x=P_0+(b/a-1)P_0/2`
`x=P_0/2`
`P_A=P_0-x=P_0-P_0/2=P_0/2`
`P_A` reduces to half in 10 min, so `t_(t//2)`=10 min


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