1.

For a 5% solution of urea (Molar mass = 60 g/mol), calculate the osomotic pressure at 300 K. [R=0.0821 " L atm K"^(-1)"mol"^(-1)]

Answer»

Solution :Applying the relation : `PI =CRT`,
where C is the number of moles per litre of the solution.
Let US CONSIDER one litre of the solution.
Mass of the solute in one litre = 50 g
Number of moles of the solute `=(50)/(6)`
Concentration, `C=(5)/(6)`
Substitutingthe values in the above equation, we have
`pi=(5)/(6) xx 0.0821 xx 300`
`=20.525` atm


Discussion

No Comment Found