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For a 5% solution of urea (Molar mass = 60 g/mol), calculate the osomotic pressure at 300 K. [R=0.0821 " L atm K"^(-1)"mol"^(-1)] |
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Answer» Solution :Applying the relation : `PI =CRT`, where C is the number of moles per litre of the solution. Let US CONSIDER one litre of the solution. Mass of the solute in one litre = 50 g Number of moles of the solute `=(50)/(6)` Concentration, `C=(5)/(6)` Substitutingthe values in the above equation, we have `pi=(5)/(6) xx 0.0821 xx 300` `=20.525` atm |
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