1.

For a Ag -Zn button cell , net reaction is : Zn_((s) + Ag_2 O_((s)) to ZnO_((s)) + 2Ag_((s)) , DeltaG^(0)f (Ag_2O) = -11 . 21 kJmol^(-1)DeltaG^(0)F (ZnO) = -318 . 3 kJ mol^(-1) HenceE_("cell")^(0) of the button cell is :

Answer»

`3.182 V `
`1.71 V `
`-1.591V `
`1.591V `

Solution :`DeltaG^(0) = DeltaG_f "(products)" - DeltaG_f " (reactant)"= -318 .3- (11.21) = -3.07 XX 10^(3)` in KJ ........... (1)
`DeltaG^(0) = -nF E^(0)` ......... (2) `:. -nfE^(0) = -307 xx 10^(3)`
` 2 xx 96500 xx E^(0) = 307 xx 10^(3) , E^(0) = (3.07 xx 10^(3))/(2 xx 96500) = + 1.59V`


Discussion

No Comment Found

Related InterviewSolutions