For a binary liquid solution of A and B. P_A^0=pure vapour pressure of A . P_B^0=pure vapour pressure of B. X_A=mole fraction of A in liquid phase.Y_A=mole fraction of A in vapour phase. {:("Column I","Column II"),((A)P_A^0gtP_B^0"[Ideal liquid solution]",(p)X_A=Y_A),((B)"Azeotropic mixture",(q)X_AltY_A),(( C)"Equimolar ideal mixture of A & B with "P_A^0ltP_B^0,(r)X_BltY_B),((D)"Equimolar ideal mixture of A & B with "P_A^0=P_B^0,(s)Y_BgtY_A),(,(t)X_B=Y_B):}

For a binary liquid solution of A and B. P_A^0=pure vapour pressure of

1.	For a binary liquid solution of A and B. P_A^0=pure vapour pressure of A . P_B^0=pure vapour pressure of B. X_A=mole fraction of A in liquid phase.Y_A=mole fraction of A in vapour phase. {:("Column I","Column II"),((A)P_A^0gtP_B^0"[Ideal liquid solution]",(p)X_A=Y_A),((B)"Azeotropic mixture",(q)X_AltY_A),(( C)"Equimolar ideal mixture of A & B with "P_A^0ltP_B^0,(r)X_BltY_B),((D)"Equimolar ideal mixture of A & B with "P_A^0=P_B^0,(s)Y_BgtY_A),(,(t)X_B=Y_B):}
Answer» Solution :(A)`P_A^0gt P_B^0` MEANS A is more VOLATILE than B and therefore A will be RICHER in vapour PHASE , [or `Y_A=X_A(P_A^0)/P_T`] (B)For azeotropes composition of vapour phase and liquid phase is same (C )For `P_A^0 lt P_B^@ ,X_B lt Y_B and Y_B GT Y_A` for an equimolar ratio. (D) For `P_A^0=P_B^0,X_A=Y_A` for an equimolar ratio.