1.

For a BJT circuit shown , assume that the 'beta' of the transistor is very large and V_(BE)=0.7V. The mode of operation.

Answer»

Solution :`V_(BE)=0.7V`
Input junction is a forward BIASED .
SINCE ,
`V_(BE)=0.7V`
`V_(CE)=V_(BE)+V_(CB)`
`V_(CB)=V_(CE)-V_(BE)`
To determine `V_(CB)` we find `I_(C)`
`I_(C) -=I_(C)=(2-V_(BE))/(R_(2))=(2-0.7)/(1kOmega)`
`I_(C)=1.3mA`
`V_(CE)=V_("CC")-I_(C)(R_(1)+R_(2))`
`=10-1.3mA (10K+1K)`
`V_(CE)=-4.3V`
`V_(CE)=-4.3V-0.7`
`V_(CB)=-5V`


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