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For a body, angular velocity `vecomega= hati-2hatj+3hatk` and radius vector `vecr=hati+hatj+hatk`, then its velocity `(vecv= vecomega xx vecr)` is :A. `-5hati+2hatj+3 hatk`B. `-5hati+2hatj-3 hatk`C. `-5hati-2hatj+3 hatk`D. `-5hati-2hatj-3 hatk` |
Answer» Correct Answer - A `vecv=vecwxxvecr` `|{:(hati , hatj , hatr), (1 , -2 , 3), (1 , 1, 1):}|` `=hati(-2-3)-hatj(1-3)+hatk(1+2)` `=-5hati+2hatj+3hatk` |
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