For a capacitor the distane between two plates is 4x and the electric field between them is E_(0). Now a dielectric slab having dielectric constant 3 and thickkness x is placed between them in contact with one plate. In this condition what is the p.d. between its two plates ?

For a capacitor the distane between two plates is 4x and the electric

1.	For a capacitor the distane between two plates is 4x and the electric field between them is E_(0). Now a dielectric slab having dielectric constant 3 and thickkness x is placed between them in contact with one plate. In this condition what is the p.d. between its two plates ?
Answer» `(10 E_(0)x)/(3)` `(11E_(0)x)/(3)` `(13 E_(0)x)/(3)` `(9E_(0)x)/(3)` Solution :`V = (E_(0))/(K) x+3 E_(0)x ` `= (E_(0))/(3) x+ 3E_(0)x = (E_(0)x+9E_(0)x)/(3) = (10E_(0)x)/(3)`

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For a capacitor the distane between two plates is 4x and the electric field between them is E_(0). Now a dielectric slab having dielectric constant 3 and thickkness x is placed between them in contact with one plate. In this condition what is the p.d. between its two plates ?

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