1.

For a carnot engine, the source is at 500 K and the sink at 300 K. What is efficiency of this engine

Answer»

0.2
0.4
0.6
0.3

Solution :Given that, `T_(1)` = 500K, `T_(2)`=300 K
By USING,`eta=(T_(1)-T_(2))/(T_(1))=(500-300)/(500)=(200)/(500)=0.4`


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