1.

For a cell involving two electrons changes, E_(cell)^(@)=0.3" V" at 25^(@)C. The equilibrium constant for the reaction is :

Answer»

`10^(10)`
`3XX10^(-2)`
10
`10^(10)`

SOLUTION :`logK_(C )=(nE_(cell)^(@))/(0.0591)=((2xx0.3" V"))/((0.0591" V"))~~=10`.
`K_(C )="Antilog "10=10^(10)`


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