1.

For a cell reaction involving a two-electron change, the standard emf of the cell is found to be 0.295 V at 25^@C. the equilibrium constant of the reaction at 25^(@)C will be

Answer»

`1xx10^(-10)`
`29.5xx10^(-2)`
`10`
`1xx10^(10)`

SOLUTION :`DeltaG=-nFE^(o)`
`DeltaG=-2.303RT" log "K,nFE^(o)=2.303RTlogK`
`LOGK=(nFE^(o))/(2.303RT)=(2xx96500xx0.295)/(2.303xx8.314xx298)`
`logK=9.97=K=1xx10^(10)`


Discussion

No Comment Found

Related InterviewSolutions