For a cell terminal potential difference is 2.2 V when circuit is open and reduces to 1.8V when cell is connected to a resistance of R=`5Omega` then determine internal resistance of cell is:-A. `10/9Omega`B. `9/10Omega`C. `11/9Omega`D. `5/9Omega`

For a cell terminal potential difference is 2.2 V when circuit is open

1.	For a cell terminal potential difference is 2.2 V when circuit is open and reduces to 1.8V when cell is connected to a resistance of R=`5Omega` then determine internal resistance of cell is:-A. `10/9Omega`B. `9/10Omega`C. `11/9Omega`D. `5/9Omega`
Answer» Correct Answer - A T.P.D (V)=E-Ir (Remember it) V=E-`(E/(R+r))r="ER"/"(R+r)"` from given conditions E=2.2 & when R=5 then TPD V =1.8 V therefore 1.8=`(2.2xx5)/(5+r) rArr r=10/9 Omega`

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For a cell terminal potential difference is 2.2 V when circuit is open and reduces to 1.8V when cell is connected to a resistance of R=`5Omega` then determine internal resistance of cell is:-A. `10/9Omega`B. `9/10Omega`C. `11/9Omega`D. `5/9Omega`

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