For a certain hypothetical one electron atom, the wavelength `(in Å)` for the spectral lines for transitions originating at n=p and terminating at n=1 are given by `lambda = (1500 p^2)/(p^2 - 1), where p = 2,3,4` (a)Find the wavelength of the least energetic and the most energetic photons in this series.(b) Construct an energy level diagram for this element showing the energies of the lowest three levels. (c ) What is the ionization potential of this element?A. The wavelength of the least energetic and the most energetic photons in this series is `2000 Å, 1500Å`.B. Difference between energies of fourth and third orbit is `0.40 eV`.C. Energy of second orbit is `6.2 eV`D. The ionisation potential of this element is `8.27 eV`.

For a certain hypothetical one electron atom, the wavelength `(in Å)`

1.	For a certain hypothetical one electron atom, the wavelength `(in Å)` for the spectral lines for transitions originating at n=p and terminating at n=1 are given by `lambda = (1500 p^2)/(p^2 - 1), where p = 2,3,4` (a)Find the wavelength of the least energetic and the most energetic photons in this series.(b) Construct an energy level diagram for this element showing the energies of the lowest three levels. (c ) What is the ionization potential of this element?A. The wavelength of the least energetic and the most energetic photons in this series is `2000 Å, 1500Å`.B. Difference between energies of fourth and third orbit is `0.40 eV`.C. Energy of second orbit is `6.2 eV`D. The ionisation potential of this element is `8.27 eV`.
Answer» Correct Answer - A::B::C::D

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