1.

For a certain reaction `X`rarr`Y` the value of `DeltaH` and `DeltaS` are `50.50KJ mol^(-1)` and `100.03JK^(-1)` respectively. The temperature at which `DeltaG=0` isA. `505^(@)C`B. `232^(@)C`C. `252^(@)C`D. `450^(@)C`

Answer» Correct Answer - A
Given, `DeltaH=50.50KJ mol^(-1)`
`DeltaS=100JK^(-1)=100xx10^(-3)=0.1KJK^(-1)`
`:.` From `DeltaG=DeltaH-TDeltaS`
`implies 0=DeltaH-TDeltaS`
`implies T=(DeltaH)/(DeltaS)=(50.50)/(0.1)=505K`
`:. T=505-273=232^(@)C`


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