1.

For a chemical reaction A_2 +2 B toProducts, the rate con trolling step is A=1/2B to C.If the cone. of B is tripled, the rate of reaction will

Answer»

remain the same
BECOME four times
become 1.732 times
become DOUBLE

Solution :The SLOW step of the reaction is :
`A + 1/2B to C, " rate LOW is,"(dx)/(dt)=k[A][B]^(1//2)`
On TRIPLING the concentration of B, the rate will become `(3)^(1//2)= 1.732` times of the original rate.


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