1.

For a chemical reaction at 27^(@)C, the activation energy is 600 R. The ratio of the rate constants at 327^(@)C to that of at 27^(@)C will be

Answer»

2
40
E
`e^2`

Solution :In`(k_2)/(k_1)=(E_a)/(R) ((1)/(T_1)-(1)/(T_2))`
or, In`(k_2)/(k_1)=(600R)/(R) ((1)/(300)-(1)/(600))`
or, In `(k_2)/(k_1)=(600R)/(R)((2-1)/(600))=1`
or, In`(k_2)/(k_1)`=In e(`therefore` In e=1)
`(k_2)/(k_1)=e`


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