1.

For a chemical reaction Ato products, the following equation is found to be followed, logK=16.398-2800/T Activation energy of the reaction is _____________K.Cal

Answer»

128.13
12.767
12813
1.2813

Solution :`(EA)/(2.303RT)=2800/TimpliesEa=2800xx2.303xx1.98=12.76` KCAL


Discussion

No Comment Found