1.

For a chemical reaction Y_2 + 2Z toProduct,rate conctrolling step is Y + 1/2 Z to Q If the concentration of Z is doubled, the rate of reaction will

Answer»

remain the same
become four times
become `sqrt2` times
become double.

Solution :`"Rate"_1=k[Y][Z]^(1/2) and "Rate"_2 =k[Y][2Z]^(1/2)`
`:.("Rate"_2)/("Rate"_1)=(k[A][2Z]^(1//2))/(k[Y][Z]^(1//2))=(2)^(1//2)=sqrt2`


Discussion

No Comment Found

Related InterviewSolutions