For a consecutive reaction R1k1−→R2 R1k2−→R3 If initial conce – InterviewSolution

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1.	For a consecutive reaction R1k1−→R2 R1k2−→R3 If initial concentration of R1 is 100 M and k1:k2=1:0.15 the value of [R2]max is [Given:k1=4.0×10−2min−1]
Answer» For a consecutive reaction $R_{1} k_{1} - \to R_{2} R_{1} k_{2} - \to R_{3}$ If initial concentration of $R_{1}$ is 100 M and $k_{1} : k_{2} = 1 : 0.15$ the value of $[R_{2}]_{m a x}$ is $[G i v e n : k_{1} = 4.0 \times 10^{- 2} m i n^{- 1}]$

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