1.

For a d-electron the orbital angular momentum is

Answer»

h
`sqrt6h/(2pi)`
`sqrt2h`
`sqrt6h`

SOLUTION :For a d-clcctron, l = 2
ORBITAL ANGULAR MOMENTUM = `sqrt(l(l+1))h/(2pi)`
`=sqrt(2(2+1))h/(2pi)=sqrt6h/(2pi)=sqrt6h`


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