For a dilute solution containing 2.5 g of a non-volatile non-electrolyte solution in 100g of water, the elevation in boiling point at 1 atm pressure is 2^(@)C. Assuming concentrationof solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is: (take k_(b) = 0.76 K kg mol^(-1))

For a dilute solution containing 2.5 g of a non-volatile non-electroly

1.	For a dilute solution containing 2.5 g of a non-volatile non-electrolyte solution in 100g of water, the elevation in boiling point at 1 atm pressure is 2^(@)C. Assuming concentrationof solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is: (take k_(b) = 0.76 K kg mol^(-1))
Answer» 724 740 736 718 Solution :`DeltaT_(B)=K_(b)xxm` `2=0.76xxm ""IMPLIES""m=2/0.76` `m=(w_(2)xx1000)/(M_(2)xxW_(1)("in grams"))=2.5/(M_(2)xx100)xx1000` `2/0.76=(2.5xx10)/(M_(2))impliesM_(2)=(2.5xx10)/2xx0.76` `(p_("SOLVENT")^(@)-p_("solutte"))/(p_("solvent")^(@))=x_("solute")` `p_("solvent")^(@)=1atm=760` MM Hg `(760-p_("solvent")^(@))/760=(2.5//M_(2))/(100//18)` `760-p_("solute")=(2.5xx2)/(2.5xx10xx0.76)xx18/100xx760` `760-p_("solute")=36impliesp_("solute")=724` mm hg