1.

For a dilute solution containing 2.5 g of a non-volatile, non-electrolytic solute in 100 g of water, the elevation in boiling point at 1 atm pressure is 2^(@)C. Assuming concentration of the solute is much lower than the concentration of the solvent, the vapour pressure (mm of Hg) of the solution is (take K_(b)="0.76 K kg mol"^(-1))

Answer»

<P>724
740
736
718

Solution :`M_(2)=(1000K_(B)w_(2))/(w_(1)xxDeltaT_(b))=(1000xx0.76xx2.5)/(100xx2)=9.5`
`(p^(@)-p_(s))/(p^(@))=x_(2)=(n_(2))/(n_(1)+n_(2))=(n_(2))/(n_(1))""(" as " n_(2) lt lt n_(1))`
`=(w_(2)//M_(2))/(w_(1)//M_(1))`
`(760-p_(s))/(760)=(2.5//9.5)/(100//18)=0.047`
`or 760-p_(s)=760xx0.047=35.7`
`or""p_(s)=724.3mm`


Discussion

No Comment Found