1.

For a first order reaction A to P, the temperature (T) dependent rate constsant (k) was found to follow the equation logk=-(2000)(1)/(T)+6.0 The per-exponential factor A and the activation energy E_(a), respectively, are

Answer»

`1.0xx10^(6)s^(-1)" and "9.2" kJ mol"^(-1)`
`6.0" s"^(-1)" and "16.6" kJ mol"^(-1)`
`1.0xx10^(-1)s^(-1)" and "16.6" kJ mol"^(-1)`
`1.0xx10^(6)s^(-1)" and "38.3" kJ mol"^(-1)`

Solution :GIVEN log `K=6-2000/T`
COMPARING with log `k=log A - E_a/(2*303RT)`
`log A=6, i.e., A = 10^(6)s^(-1)" and "E_a/(2*303R)=2000`
or `E_a=2000xx2*303xx8*314" J mol"^-1`
`= 38294" J mol"^-1 = 38*3" kJ mol"^-1`


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