1.

For a first order reaction ArarrB the rate constant is x "min"^(-1) . If the initial concentration of A is 0.01 M, the concentration of A after one hour is given by the expression.

Answer»

`0.01e^(-x)`
`1xx10^(-2)(1-E^(-60x))`
`(1xx10^(-2))e^(-60x)`
NONE of these

Solution :`k=((2.303)/(t))log(([A_0])/([A]))`
`k=(1/t)ln(([A_0])/([A]))`
`e^(kt)=(([A_0])/([A]))`
`[A]=[A_0]e^(kt)` In this case
`k = x "min"^(-1)and [A_0]=0.01M`
`=1xx10^(-2)M`
t = 1 HOUR = 60 min
`[A]=1xx10^(-2)(e^(-60x))`


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