1.

For a first order reaction -(d[A])/(dt)=K[A]_(0), the reaction is carried out by taking 100mol//L then concentration of A decayed after time (1)/(K) is :

Answer»

`53.21 mol//L`
`36.79 mol//L`
`61.21 mol//L`
`26.79 mol//L`

SOLUTION :`[A]=[A]_(0)E^(-Kt)=100xxe^(-k//k)`
`=(100)/(e )=(100)/(2.718)=36.79mol//L`
`:.[A]` decayed `=16.21`


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