1.

For a first order reaction, if the time taken for completion of 50% of the reactionis t second, the time required for completion of 99.9% of the reaction is:

Answer»

10t
5t
100t
2t

Solution :`(Kxxt_(1))/(Kxxt_(2))=("LOG"100/50)/("log"100/0.1)impliest/(t_(2))=(log_(2))/(3log_(10)^(10)),t_(2)=(txx3)/0.3010=10xxt`


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