1.

For a first order reaction, it takes 5 minutes for the initial concentration of 0.6" mol L"^(-1) to become 0.4" mol L"^(-1). How long in all will it take for the initial concentration to become 0.3" mol L"^(-1) ?

Answer»


SOLUTION :`a=0.6" MOL L"^(-1),(a-x)=0.4" mol L"^(-1),t=5" min",""K=(2.303)/(5" min")log""(0.6)/(0.4)=0.0811" min"^(-1),`
`0.6" mol L"^(-1)to0.3" mol L"^(-1)"means "t_(1//2).` Hence, `t_(1//2)=(0.693)/(0.0811" min"^(-1))=8.54" min".`


Discussion

No Comment Found

Related InterviewSolutions