1.

For a first order reaction t_(0.75) is 1368 seconds, therefore, the specific rate constant in sec^(-1) is

Answer»

`10^(-3)`
`10^(-2)`
`10^(-9)`
`10^(-5)`

Solution :`k=(2.303)/(1386)"LOG"(100)/(100-75)` on solving we GET, `k=10^(-3)`


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