1.

For a first order reaction , the rate constant is 6.909 "min"^(-1) . The time taken for 75% conversion in minutes is ........

Answer»

`(3/2)LOG2`
`(2/3)log2`
`(3/2)log(3/4)`
`(2/3)log(4/3)`

Solution :`k=((2.303)/t)log.(([A_0])/([A]))`
`[A_0]=100,[A]=25`
`6.909=((2.303)/t)log(100/25)`
`t=(2.303)/(6.909)log(4)impliest=(1/3)log2^2`
`t = (2/3)log2`


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