1.

For a first order reaction velocity constant , K = 10^(-3) s^(-1) . Two third life for it would be

Answer»

1100 s
2200 s
3300 s
4400 s

Solution :We know that `k = (2.303)/(t)` log `(a)/(a-x)`
`10^(-3) = (2.303)/(t)` log `(a)/((a - (2a)/(3))) , 10^(-3) = (2.303)/(t)` log 3
`10^(-3) = (2.303)/(t) xx 0.4771 , t = (2.303 xx 0.4771)/(10^(-3))`
`= 1098.7` SEC = 1100 sec .


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